## Posts

Showing posts from May, 2018

### A few takeaways from PyCon, 2018

There were a lot of interesting talks this year, and although I didn't attend nearly as many talks as I would have liked, I got a lot out of those that I did.
Performance Python First and foremost has to be Jake Vanderplas' talk, Performance Python: Seven Strategies for Optimizing Your Numerical Code. My first takeaway from his talk is line_profiler, which is a command line tool that's intended to be used to profile your Python functions' execution time, line-by-line.

For example, let's use code from my last post and apply the convert function to a single image. We use line_profiler in the terminal by adding the @profile decorator to the function head (no imports necessary).
@profile def convert(im: np.array, transform: np.array) -> np.array: """ Convert an image array to another colorspace """ dimensions = len(im.shape) axes = im.shape[:dimensions-1] # Create a new array (respecting mutability) new_ = np.empty(…

### Color space conversion I've been intrigued by Steven Pigeon's series on color spaces lately and wanted to give color space conversion a try in Python. In the following script I've reproduced several of the color spaces Pigeon mentions in the first five parts of the series.

Using NumPy this operation is almost trivial, but I added a few fun tidbits as well. Also note that, as I've mentioned before, PEP 465 has added the infix matrix multiplication operator @ to Python 3.5+.
#! /usr/bin/env python3.6 # -*- coding: utf-8 -*- # vim:fenc=utf-8 """ Convert colorspaces. """ from typing import List from tqdm import tqdm from functools import reduce from operator import mul import numpy as np import imageio import os ## Colorspaces Kodak_1 = np.array([[ 1, 1, 1], [-1, -1, 1], [ 1, -1, -1]]) Kodak_YCC = np.array([[ 0.299, 0.587, 0.114], [-0.299, -0.587, 0.886], [ 0.701, -0.58…

### Fold a String into an Int type

While working my way through (Sullivan, Goerzen & Stewart, 2009), I came across the problem of converting a String to an Int using folds. This isn't that difficult a problem, but because I'm still a beginner to Haskell, I had to think about it for a few days.

Finally, I came up with the following (unsafe) solution using foldl.
import Data.Char (digitToInt) asInt :: String -> Int asInt [] = 0 asInt (x:xs) | x == '-' = (-1) * asInt xs | otherwise = sum $foldl helper []$ zip (reverse [0..(length (x:xs) - 1)]) (x:xs) where helper :: [Int] -> (Int,Char) -> [Int] helper totalList (order,digit) = digitToInt digit * 10 ^ order : totalList I separated the state of summing from the rest of the problem, using the fold to  'loop' over the list and raise each digit to the appropriate magnitude based on its position, just as one would in an imperative language. Thus, I believe this is a hybrid solution that uses both recursion and a f…